A boy jumps at a speed of 20.0 m/s at an angle of 25.0° above the horizontal. What is the horizontal component of the boy's velocity?
A) 12.6 m/s
B) 8.5 m/s
C) 18.1 m/s
D) 15.6 m/s
E) 20.0 m/s

Question

Quizplus · Accepted Answer

The horizontal component of the velocity can be found using the formula $v_x = v \cos(\theta)$, where $v = 20.0 \, \text{m/s}$ is the initial velocity and $\theta = 25.0^\circ$ is the angle. Calculating this gives $v_x = 20.0 \cos(25.0^\circ) \approx 18.1 \, \text{m/s}$.

A Boy Jumps at a Speed of 20