Question 1

Number of defects = 350; opportunities for a defect to occur = 10; number of units = 1,000
-To achieve a percentage of defect-free output of 99.38, what would be the number of defects?
A)1
B)62
C)228
D)2
E)14

Accepted Answer

The answer of Number of defects = 350; opportunities for...

Question 2

Number of defects = 350; opportunities for a defect to occur = 10; number of units = 1,000
-To achieve a defects per million opportunities (DPMO) value of 32, what would be the number of defects?
A)1
B)62
C)228
D)2
E)14

Accepted Answer

The answer of Number of defects = 350; opportunities for...

Question 3

A firm recently produced 7,778 units, with a total defect level of 90. Each unit can have 32 defects.
-What is the firm's probable DPMO?
A)2,765
B)457,130
C)362
D)21,875
E)27,007

Accepted Answer

The answer of A firm recently produced 7,778 units, with...

Question 4

A firm recently produced 7,778 units, with a total defect level of 90. Each unit can have 32 defects.
-What will be your best choice for the firm's Six Sigma operating level?
A)Better than 5.5
B)Better than 5
C)Better than 6
D)Better than 4.5
E)Better than 4

Accepted Answer

The answer of A firm recently produced 7,778 units, with...

Question 5

A firm recently produced 7,778 units, with a total defect level of 90. Each unit can have 32 defects.
-To achieve a percentage of defect-free output of 99.977, what would be the defect level?
A)1
B)8
C)32
D)336
E)58

Accepted Answer

The answer of A firm recently produced 7,778 units, with...

Question 6

A firm recently produced 7,778 units, with a total defect level of 90. Each unit can have 32 defects.
-To achieve a defects per million opportunities (DPMO) value of 32, what would be the defect level?
A)1
B)8
C)32
D)336
E)58

Accepted Answer

To achieve a DPMO of 32, the defect level should be 8. DPMO is calculated as (Defects / (Units * Opportunities per unit)) * 1,000,000. Solving for defects: 32 = (Defects / (7778 * 32)) * 1,000,000, which gives Defects = 8.

Question 7

A firm recently produced 7,778 units, with a total defect level of 90. Each unit can have 32 defects.
-To achieve a sigma level of 6, what would be the defect level?
A)1
B)8
C)32
D)336
E)58

Accepted Answer

To achieve a Six Sigma level, the defect rate must be extremely low, typically around 3.4 defects per million opportunities (DPMO). Given the number of units and potential defects, the defect level should be close to 1 to meet the Six Sigma standard.

Question 8

The St. Helena Heritage Center at Marquette, Michigan, wants to start analyzing their company's customer service quality. For each type of service the center provides, there are 6 types of customer complaints. During the last 12 months, the center had 8,876 visitors and received a total of 1,253 complaints.
-What is the center's DPMO for the past 12 months?
A)43
B)1,853,605
C)11,806
D)23,528
E)5,395

Accepted Answer

The answer of The St. Helena Heritage Center at Marquette,...

Question 9

The St. Helena Heritage Center at Marquette, Michigan, wants to start analyzing their company's customer service quality. For each type of service the center provides, there are 6 types of customer complaints. During the last 12 months, the center had 8,876 visitors and received a total of 1,253 complaints.
-What will be your best choice for the center's Six Sigma operating level?
A)Better than 3.5
B)Better than 5
C)Better than 3
D)Better than 4.5
E)Better than 4

Accepted Answer

The defect rate is 1,253 complaints out of 8,876 visitors, which is approximately 14.11%. This defect rate corresponds to a Six Sigma level slightly better than 3.

Question 10

The St. Helena Heritage Center at Marquette, Michigan, wants to start analyzing their company's customer service quality. For each type of service the center provides, there are 6 types of customer complaints. During the last 12 months, the center had 8,876 visitors and received a total of 1,253 complaints.
-To achieve a defects per million opportunities (DPMO) value of 6,210, what would be the number of complaints?
A)331
B)72
C)1,253
D)2
E)12

Accepted Answer

DPMO = (Number of defects / Number of opportunities) * 1,000,000DPMO = (Number of complaints / Number of visitors) * 1,000,0006,210 = (Number of complaints / 8,876) * 1,000,000Number of complaints = 6,210 * 8,876 / 1,000,000Number of complaints = 55.22Since the number of complaints cannot be a fraction, the closest whole number is 55.

Question 11

The St. Helena Heritage Center at Marquette, Michigan, wants to start analyzing their company's customer service quality. For each type of service the center provides, there are 6 types of customer complaints. During the last 12 months, the center had 8,876 visitors and received a total of 1,253 complaints.
-To achieve a sigma level of 5, what would be the number of complaints?
A)331
B)72
C)1,253
D)2
E)12

Accepted Answer

The answer of The St. Helena Heritage Center at Marquette,...

Question 12

The St. Helena Heritage Center at Marquette, Michigan, wants to start analyzing their company's customer service quality. For each type of service the center provides, there are 6 types of customer complaints. During the last 12 months, the center had 8,876 visitors and received a total of 1,253 complaints.
-To achieve a percentage of defect-free output of 99.865, what would be the number of complaints?
A)331
B)72
C)1,253
D)2
E)12

Accepted Answer

The answer of The St. Helena Heritage Center at Marquette,...

Question 13

Romeo and Juliet make and sell cookies for their online business, Heartbreak Abode. They want to track quality, so they decide to calculate their defects per million opportunities, or DPMO, each month. For each box of cookies they sell, there can be 7 possible defects or customer complaints. During the last month, Heartbreak filled 725 orders. They received 49 complaints.
-Calculate Heartbreak's DPMO during the past month.
A)21,137
B)1,970,443
C)5,075
D)106
E)9,655

Accepted Answer

To calculate DPMO, use the formula: DPMO = (Number of Defects / (Number of Units * Number of Opportunities per Unit)) * 1,000,000. Here, Defects = 49, Units = 725, Opportunities per Unit = 7. DPMO = (49 / (725 * 7)) * 1,000,000 = 9,655.17, rounded to 9,655.

Question 14

Romeo and Juliet make and sell cookies for their online business, Heartbreak Abode. They want to track quality, so they decide to calculate their defects per million opportunities, or DPMO, each month. For each box of cookies they sell, there can be 7 possible defects or customer complaints. During the last month, Heartbreak filled 725 orders. They received 49 complaints.
-What will be your best choice for the center's Six Sigma operating level?
A)Better than 3.5
B)Better than 5
C)Better than 3
D)Better than 4.5
E)Better than 4

Accepted Answer

The answer of Romeo and Juliet make and sell cookies...

Question 15

Romeo and Juliet make and sell cookies for their online business, Heartbreak Abode. They want to track quality, so they decide to calculate their defects per million opportunities, or DPMO, each month. For each box of cookies they sell, there can be 7 possible defects or customer complaints. During the last month, Heartbreak filled 725 orders. They received 49 complaints.
-To achieve a defects per million opportunities (DPMO) value of 233, what would be the number of complaints?
A)49
B)32
C)1
D)7
E)115

Accepted Answer

The DPMO formula is: DPMO = (Number of defects / Number of opportunities) x 1,000,000. In this case, the number of opportunities is the number of boxes of cookies sold, which is 725. The number of defects is the number of complaints, which is 49. So, the DPMO is: DPMO = (49 / 725) x 1,000,000 = 67,647. To achieve a DPMO value of 233, the number of complaints would need to be: Number of complaints = (DPMO x Number of opportunities) / 1,000,000 = (233 x 725) / 1,000,000 = 168. Therefore, the correct answer is C) 1.

Question 16

Romeo and Juliet make and sell cookies for their online business, Heartbreak Abode. They want to track quality, so they decide to calculate their defects per million opportunities, or DPMO, each month. For each box of cookies they sell, there can be 7 possible defects or customer complaints. During the last month, Heartbreak filled 725 orders. They received 49 complaints.
-To achieve a percentage of defect-free output of 99.865, what would be the number of complaints?
A)49
B)32
C)1
D)7
E)115

Accepted Answer

The answer of Romeo and Juliet make and sell cookies...

Question 17

Romeo and Juliet make and sell cookies for their online business, Heartbreak Abode. They want to track quality, so they decide to calculate their defects per million opportunities, or DPMO, each month. For each box of cookies they sell, there can be 7 possible defects or customer complaints. During the last month, Heartbreak filled 725 orders. They received 49 complaints.
-To achieve a sigma level of 4, what would be the number of complaints?
A)49
B)32
C)1
D)7
E)115

Accepted Answer

To achieve a sigma level of 4, the DPMO should be approximately 6,210. With 725 orders and 7 opportunities per order, the total opportunities are 5,075. To find the number of complaints for a sigma level of 4, solve for X in the equation (X/5,075) * 1,000,000 = 6,210, which gives approximately 32 complaints.

Quiz 13: Supplement: Statistical Quality Control and Six Sigma Quality Management

Number of defects = 350; opportunities for a defect to occur = 10; number of units = 1,000 -To achieve a percentage of defect-free output of 99.38, what would be the number of defects?

Number of defects = 350; opportunities for a defect to occur = 10; number of units = 1,000 -To achieve a defects per million opportunities (DPMO) value of 32, what would be the number of defects?

A firm recently produced 7,778 units, with a total defect level of 90. Each unit can have 32 defects. -What is the firm's probable DPMO?

A firm recently produced 7,778 units, with a total defect level of 90. Each unit can have 32 defects. -What will be your best choice for the firm's Six Sigma operating level?

A firm recently produced 7,778 units, with a total defect level of 90. Each unit can have 32 defects. -To achieve a percentage of defect-free output of 99.977, what would be the defect level?

A firm recently produced 7,778 units, with a total defect level of 90. Each unit can have 32 defects. -To achieve a defects per million opportunities (DPMO) value of 32, what would be the defect level?

A firm recently produced 7,778 units, with a total defect level of 90. Each unit can have 32 defects. -To achieve a sigma level of 6, what would be the defect level?