Find the two unit vectors tangent at the point (1, 1, 1) to the curve of intersection of the surfaces xy² + x²y + z³ = 3 and x³ - y³ - xyz = -1. A) ± ( i + j - 2 k ) B) ± ( i - j - 2 k ) C) ± ( i - 2 j - 2 k ) D) ± ( i + j - k ) E) ± ( i + j - 2 k )

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The Answer of Find the two unit vectors tangent at the point (1, 1, 1) to the curve of intersection of the surfaces xy² + x²y + z³ = 3 and x³ - y³ - xyz = -1. A) ± ( i + j - 2 k ) B) ± ( i - j - 2 k ) C) ± ( i - 2 j - 2 k ) D) ± ( i + j - k ) E) ± ( i + j - 2 k )

Find the Two Unit Vectors Tangent at the Point (1