Find an equation of the plane tangent to the surface xy³z² = 2 at the point (2, 1, -1). A) x = (2 + t) i + (1 + 6t) j + (-1 - 4t) k, t R B) x + 6y + 4z = 4 C) x + 6y - 4z = 12 D) x + 6y - 4z = 0 E) x + 5y - 4z = 11

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The Answer of Find an equation of the plane tangent to the surface xy³z² = 2 at the point (2, 1, -1). A) x = (2 + t) i + (1 + 6t) j + (-1 - 4t) k, t R B) x + 6y + 4z = 4 C) x + 6y - 4z = 12 D) x + 6y - 4z = 0 E) x + 5y - 4z = 11

Find an Equation of the Plane Tangent to the Surface