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You Probably Know by Now That a Differential K-Form K \ge

Question 35

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You probably know by now that a differential k-form k \ge 1 on a domain D  You probably know by now that a differential k-form k  \ge  1 on a domain D      is very similar to a vector field on D, and hence a correspondence between the two may be established.Let   = F dx + G dy + H dz be a differential 1-form on a domain D      and let   be the vector field corresponding to   . Using this set up, find the vector differential identity corresponding to the fact      =   . A)   \bigtriangledown  (divF)  = 0 B)  curl(F)  = 0 C)  div(curl F) = 0 D)    F = 0 E)  curl(curl F)  = 0  You probably know by now that a differential k-form k  \ge  1 on a domain D      is very similar to a vector field on D, and hence a correspondence between the two may be established.Let   = F dx + G dy + H dz be a differential 1-form on a domain D      and let   be the vector field corresponding to   . Using this set up, find the vector differential identity corresponding to the fact      =   . A)   \bigtriangledown  (divF)  = 0 B)  curl(F)  = 0 C)  div(curl F) = 0 D)    F = 0 E)  curl(curl F)  = 0 is very similar to a vector field on D, and hence a correspondence between the two may be established.Let  You probably know by now that a differential k-form k  \ge  1 on a domain D      is very similar to a vector field on D, and hence a correspondence between the two may be established.Let   = F dx + G dy + H dz be a differential 1-form on a domain D      and let   be the vector field corresponding to   . Using this set up, find the vector differential identity corresponding to the fact      =   . A)   \bigtriangledown  (divF)  = 0 B)  curl(F)  = 0 C)  div(curl F) = 0 D)    F = 0 E)  curl(curl F)  = 0 = F dx + G dy + H dz be a differential 1-form on a domain D  You probably know by now that a differential k-form k  \ge  1 on a domain D      is very similar to a vector field on D, and hence a correspondence between the two may be established.Let   = F dx + G dy + H dz be a differential 1-form on a domain D      and let   be the vector field corresponding to   . Using this set up, find the vector differential identity corresponding to the fact      =   . A)   \bigtriangledown  (divF)  = 0 B)  curl(F)  = 0 C)  div(curl F) = 0 D)    F = 0 E)  curl(curl F)  = 0  You probably know by now that a differential k-form k  \ge  1 on a domain D      is very similar to a vector field on D, and hence a correspondence between the two may be established.Let   = F dx + G dy + H dz be a differential 1-form on a domain D      and let   be the vector field corresponding to   . Using this set up, find the vector differential identity corresponding to the fact      =   . A)   \bigtriangledown  (divF)  = 0 B)  curl(F)  = 0 C)  div(curl F) = 0 D)    F = 0 E)  curl(curl F)  = 0 and let  You probably know by now that a differential k-form k  \ge  1 on a domain D      is very similar to a vector field on D, and hence a correspondence between the two may be established.Let   = F dx + G dy + H dz be a differential 1-form on a domain D      and let   be the vector field corresponding to   . Using this set up, find the vector differential identity corresponding to the fact      =   . A)   \bigtriangledown  (divF)  = 0 B)  curl(F)  = 0 C)  div(curl F) = 0 D)    F = 0 E)  curl(curl F)  = 0 be the vector field corresponding to 11ee7bc6_e1d1_1134_ae82_9ddb9868f737_TB9661_11 . Using this set up, find the vector differential identity corresponding to the fact 11ee77e1_778f_e5c1_a0f8_85abfcfe325a_TB9661_11 11ee7bc6_e1d1_1134_ae82_9ddb9868f737_TB9661_11 = 11ee77e1_778f_e5c2_a0f8_6b21bea3e968_TB9661_11 .


A) \bigtriangledown (divF) = 0
B) curl(F) = 0
C) div(curl F) = 0
D) 11ee77e1_778f_e5c3_a0f8_d591926a725c_TB9661_11 F = 0
E) curl(curl F) = 0

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