Use the definition of derivative: $\lim _ { h \rightarrow 0 } \frac { f ( x + h ) - f ( x ) } { h }$ to find $f ^ { \prime } ( 1 ) \text {, if } f ( x ) = \frac { x + 1 } { x - 2 }$

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The Answer of Use the definition of derivative: $\lim _ { h \rightarrow 0 } \frac { f ( x + h ) - f ( x ) } { h }$ to find $f ^ { \prime } ( 1 ) \text {, if } f ( x ) = \frac { x + 1 } { x - 2 }$

Use the Definition of Derivative lim⁡h→0f(x+h)−f(x)h\lim _ { h \rightarrow 0 } \frac { f ( x + h ) - f ( x ) } { h }limh→0​hf(x+h)−f(x)​

Use the Definition of Derivative $\lim _ { h \rightarrow 0 } \frac { f ( x + h ) - f ( x ) } { h }$