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Suppose And limx1+f(x)f(1)x1=1\lim _ { x \rightarrow 1 ^ { + } } \frac { f ( x ) - f ( 1 ) } { x - 1 } = 1

Question 3

Multiple Choice

Suppose f(1) =2,limx1f(x) =2, and limx1+f(x) =2,limx1f(x) f(1) x1=2f ( 1 ) = 2 , \lim _ { x \rightarrow 1 ^ { - } } f ( x ) = 2 , \text { and } \lim _ { x \rightarrow 1 ^ { + } } f ( x ) = 2 , \lim _ { x \rightarrow 1 ^ { - } } \frac { f ( x ) - f ( 1 ) } { x - 1 } = - 2 and limx1+f(x) f(1) x1=1\lim _ { x \rightarrow 1 ^ { + } } \frac { f ( x ) - f ( 1 ) } { x - 1 } = 1 Is ff continuous and/or differentiable at x=1?x = 1 ?


A) f is not continuous but differentiable at x = 1
B) f is neither continuous nor differentiable at x = 1
C) f is continuous at but not differentiable at x = 1
D) f is both continuous and differentiable at x = 1

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