For a normal distribution with µ = 50 and σ = 10,the line separating the highest 10% of the scores from the rest is located at X = 51.28.

Question

Quizplus · Accepted Answer

In a normal distribution, the line separating the highest 10% of the scores (90th percentile) from the rest typically corresponds to a z-score around 1.28. Using the formula X = µ + zσ, where µ = 50 and σ = 10, the calculation would be X = 50 + (1.28)(10) = 50 + 12.8 = 62.8, not 51.28.

For a Normal Distribution with µ = 50 and σ