For a normal distribution with µ = 80 and σ = 10 the score that separates the bottom 10% of the distribution from the rest is 67.2.

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Quizplus · Accepted Answer

This statement is true. The score that separates the bottom 10% of a normal distribution is also known as the 10th percentile. Using a normal distribution calculator or z-table, we can find that a z-score of -1.28 corresponds to the 10th percentile. We can then use the formula z = (x - µ) / σ to solve for the corresponding score x: -1.28 = (x - 80) / 10, which gives x = 67.2. Therefore, the score that separates the bottom 10% of the distribution from the rest is indeed 67.2.

For a Normal Distribution with µ = 80 and σ