Let $\mathbf { F } ( x , y , z ) = x \mathbf { i } + y \mathbf { j } + z \mathbf { k }$ and S is the boundary of the region enclosed on the side by $x ^ { 2 } + y ^ { 2 } = 9$ , below by z = 0, and above z = 4. Using the Divergence Theorem, $\iint S$$\mathbf { F } \bullet \mathbf { n } d S$ is

A)72 $\pi$
B)84 $\pi$
C)96 $\pi$
D)108 $\pi$
E) $112 \pi$

Question

Let

\mathbf { F } ( x , y , z ) = x \mathbf { i } + y \mathbf { j } + z \mathbf { k }

and S is the boundary of the region enclosed on the side by

x ^ { 2 } + y ^ { 2 } = 9

, below by z = 0, and above z = 4. Using the Divergence Theorem,

\iint S

\mathbf { F } \bullet \mathbf { n } d S

is

A)72 $\pi$
B)84 $\pi$
C)96 $\pi$
D)108 $\pi$
E) $112 \pi$

Quizplus · Accepted Answer

The Answer of Let $\mathbf { F } ( x , y , z ) = x \mathbf { i } + y \mathbf { j } + z \mathbf { k }$ and S is the boundary of the region enclosed on the side by $x ^ { 2 } + y ^ { 2 } = 9$ , below by z = 0, and above z = 4. Using the Divergence Theorem, $\iint S$$\mathbf { F } \bullet \mathbf { n } d S$ is

A)72 $\pi$
B)84 $\pi$
C)96 $\pi$
D)108 $\pi$
E) $112 \pi$

Let F(x,y,z)=xi+yj+zk\mathbf { F } ( x , y , z ) = x \mathbf { i } + y \mathbf { j } + z \mathbf { k }F(x,y,z)=xi+yj+zk

Let $\mathbf { F } ( x , y , z ) = x \mathbf { i } + y \mathbf { j } + z \mathbf { k }$