The integral $\int \tan ^ { 3 } x \sec x d x$ is

A) $\frac { 3 \tan x + \tan ^ { 3 } x } { 3 } + C$
B) $\frac { \sec ^ { 3 } x + 3 \sec x } { 3 } + C$
C) $\frac { 3 \tan x - \tan ^ { 3 } x } { 3 } + C$
D) $\frac { \sec ^ { 3 } x - 3 \sec x } { 3 } + C$
E) $\frac { \sec ^ { 3 } x - 3 \tan x } { 3 } + C$

Question

The integral $\int \tan ^ { 3 } x \sec x d x$ is

A) $\frac { 3 \tan x + \tan ^ { 3 } x } { 3 } + C$
B) $\frac { \sec ^ { 3 } x + 3 \sec x } { 3 } + C$
C) $\frac { 3 \tan x - \tan ^ { 3 } x } { 3 } + C$
D) $\frac { \sec ^ { 3 } x - 3 \sec x } { 3 } + C$
E) $\frac { \sec ^ { 3 } x - 3 \tan x } { 3 } + C$

Quizplus · Accepted Answer

The Answer of The integral $\int \tan ^ { 3 } x \sec x d x$ is

A) $\frac { 3 \tan x + \tan ^ { 3 } x } { 3 } + C$
B) $\frac { \sec ^ { 3 } x + 3 \sec x } { 3 } + C$
C) $\frac { 3 \tan x - \tan ^ { 3 } x } { 3 } + C$
D) $\frac { \sec ^ { 3 } x - 3 \sec x } { 3 } + C$
E) $\frac { \sec ^ { 3 } x - 3 \tan x } { 3 } + C$

The Integral ∫tan⁡3xsec⁡xdx\int \tan ^ { 3 } x \sec x d x∫tan3xsecxdx

The Integral $\int \tan ^ { 3 } x \sec x d x$