The integral $\int \tan x \sec x d x$ is

A) $\sec ^ { 2 } x + C$
B) $\sec x + C$
C) $\tan ^ { 2 } x + C$
D) $- \sec ^ { 2 } x + C$
E) $- \tan ^ { 2 } x + C$

Question

The integral $\int \tan x \sec x d x$ is

A) $\sec ^ { 2 } x + C$
B) $\sec x + C$
C) $\tan ^ { 2 } x + C$
D) $- \sec ^ { 2 } x + C$
E) $- \tan ^ { 2 } x + C$

Quizplus · Accepted Answer

The integral of $\tan x \sec x dx$ can be solved by recognizing that the derivative of $\sec x$ is $\sec x \tan x$. Therefore, the integral $\int \tan x \sec x dx$ directly results in $\sec x + C$.

The Integral ∫tan⁡xsec⁡xdx\int \tan x \sec x d x∫tanxsecxdx Is A)

The Integral $\int \tan x \sec x d x$ Is

A)