Using the first three nonzero terms of a Maclaurin series, the approximated value of $\int _ { 0 } ^ { 1 } \frac { \sin x } { x } d x$ is

A) $\frac { 1787 } { 1800 }$
B) $\frac { 1683 } { 1800 }$
C) $\frac { 171 } { 200 }$
D) $\frac { 169 } { 200 }$
E) $\frac { 1703 } { 1800 }$

Question

Using the first three nonzero terms of a Maclaurin series, the approximated value of $\int _ { 0 } ^ { 1 } \frac { \sin x } { x } d x$ is

A) $\frac { 1787 } { 1800 }$
B) $\frac { 1683 } { 1800 }$
C) $\frac { 171 } { 200 }$
D) $\frac { 169 } { 200 }$
E) $\frac { 1703 } { 1800 }$

Quizplus · Accepted Answer

The Answer of Using the first three nonzero terms of a Maclaurin series, the approximated value of $\int _ { 0 } ^ { 1 } \frac { \sin x } { x } d x$ is

A) $\frac { 1787 } { 1800 }$
B) $\frac { 1683 } { 1800 }$
C) $\frac { 171 } { 200 }$
D) $\frac { 169 } { 200 }$
E) $\frac { 1703 } { 1800 }$

Using the First Three Nonzero Terms of a Maclaurin Series ∫01sin⁡xxdx\int _ { 0 } ^ { 1 } \frac { \sin x } { x } d x∫01​xsinx​dx

Using the First Three Nonzero Terms of a Maclaurin Series $\int _ { 0 } ^ { 1 } \frac { \sin x } { x } d x$