The Taylor series representation of $f ( x ) = \frac { 1 } { x }$ at -1 is

A) $\sum _ { n = 0 } ^ { \infty } \frac { ( n + 1 ) ^ { n } } { n ! }$
B) $\sum _ { n = 0 } ^ { \infty } ( x + 1 ) ^ { n }$
C) $\sum _ { n = 0 } ^ { \infty } \frac { ( - 1 ) ^ { n + 1 } ( x + 1 ) ^ { n } } { n }$
D) $\sum _ { n = 0 } ^ { \infty } - ( x + 1 ) ^ { n }$
E) $\sum _ { n = 0 } ^ { \infty } \frac { ( x + 1 ) ^ { n } } { 2 n ! }$

Question

The Taylor series representation of $f ( x ) = \frac { 1 } { x }$ at -1 is

A) $\sum _ { n = 0 } ^ { \infty } \frac { ( n + 1 ) ^ { n } } { n ! }$
B) $\sum _ { n = 0 } ^ { \infty } ( x + 1 ) ^ { n }$
C) $\sum _ { n = 0 } ^ { \infty } \frac { ( - 1 ) ^ { n + 1 } ( x + 1 ) ^ { n } } { n }$
D) $\sum _ { n = 0 } ^ { \infty } - ( x + 1 ) ^ { n }$
E) $\sum _ { n = 0 } ^ { \infty } \frac { ( x + 1 ) ^ { n } } { 2 n ! }$

Quizplus · Accepted Answer

The Answer of The Taylor series representation of $f ( x ) = \frac { 1 } { x }$ at -1 is

A) $\sum _ { n = 0 } ^ { \infty } \frac { ( n + 1 ) ^ { n } } { n ! }$
B) $\sum _ { n = 0 } ^ { \infty } ( x + 1 ) ^ { n }$
C) $\sum _ { n = 0 } ^ { \infty } \frac { ( - 1 ) ^ { n + 1 } ( x + 1 ) ^ { n } } { n }$
D) $\sum _ { n = 0 } ^ { \infty } - ( x + 1 ) ^ { n }$
E) $\sum _ { n = 0 } ^ { \infty } \frac { ( x + 1 ) ^ { n } } { 2 n ! }$

The Taylor Series Representation Of f(x)=1xf ( x ) = \frac { 1 } { x }f(x)=x1​

The Taylor Series Representation Of $f ( x ) = \frac { 1 } { x }$