Which of the following functions is one-to-one?

A) $f ( x ) = \frac { 1 } { e }$
B) $g ( x ) = \lfloor x - 1 \rfloor + 2$
C) $h ( x ) = \sqrt { x }$
D) $F ( x ) = 2 | x | + 3$
E) $G ( x ) = - \lfloor x \rfloor$

Question

Which of the following functions is one-to-one?

A) $f ( x ) = \frac { 1 } { e }$
B) $g ( x ) = \lfloor x - 1 \rfloor + 2$
C) $h ( x ) = \sqrt { x }$
D) $F ( x ) = 2 | x | + 3$
E) $G ( x ) = - \lfloor x \rfloor$

Quizplus · Accepted Answer

$h(x) = \sqrt{x}$ is one-to-one because for every x in its domain (x ≥ 0), there is a unique y value, and it passes the horizontal line test.

Which of the Following Functions Is One-To-One? A) f(x)=1ef ( x ) = \frac { 1 } { e }f(x)=e1​

Which of the Following Functions Is One-To-One?

A) $f ( x ) = \frac { 1 } { e }$