Which of the following functions is one-to-one?

A) $f ( x ) = \frac { 1 } { x + 1 }$
B) $g ( x ) = 2 x ^ { 2 } - 3 x + 1$
C) $h ( x ) = e ^ { 3 }$
D) $F ( x ) = - 5 | x |$
E) $G ( x ) = - \lfloor x \rfloor$

Question

Which of the following functions is one-to-one?

A) $f ( x ) = \frac { 1 } { x + 1 }$
B) $g ( x ) = 2 x ^ { 2 } - 3 x + 1$
C) $h ( x ) = e ^ { 3 }$
D) $F ( x ) = - 5 | x |$
E) $G ( x ) = - \lfloor x \rfloor$

Quizplus · Accepted Answer

Function A, $f(x) = \frac{1}{x+1}$, is one-to-one because for every x value, there is a unique y value, and it passes the horizontal line test.

Which of the Following Functions Is One-To-One? A) f(x)=1x+1f ( x ) = \frac { 1 } { x + 1 }f(x)=x+11​

Which of the Following Functions Is One-To-One?

A) $f ( x ) = \frac { 1 } { x + 1 }$