Solve $u ^ { 2 } - 16 u = 0$ by completing the square.
A) $u = - 16$
B) $u = 0 , u = - 16$
C) $u = 0 , u = 16$
D) $u = 1 , u = 16$
E) $u = 80 , u = - 48$

Question

Quizplus · Accepted Answer

To complete the square, we need to add $(16/2)^2=64$ to both sides of the equation. This gives us $u^2-16u+64=64$, which can be factored as $(u-8)^2=64$. Taking the square root of both sides gives $u-8=\pm8$, so $u=8\pm8$. Therefore, the solutions are $u=0$ and $u=16$.

Solve u2−16u=0u ^ { 2 } - 16 u = 0u2−16u=0

Solve $u ^ { 2 } - 16 u = 0$