Solve the equation by using the Square Root Property. $( 2 x + 2 ) ^ { 2 } = - 17$
A) $x = \pm \sqrt { \frac { 19 } { 2 } } i$
B) $x = \frac { - 2 \pm \sqrt { 17 } i } { 2 }$
C) $x = \pm \frac { \sqrt { 17 } i } { 2 } - 2$
D) $x = \frac { \pm 2 + \sqrt { 17 } i } { 2 }$
E) $x = 2 \pm \sqrt { 17 } i$

Question

Quizplus · Accepted Answer

Using the Square Root Property we have
$(2x+2)^2=-17$
$2x+2=\pm\sqrt{-17}i$
$2x+2=\pm i\sqrt{17}$
$2x=-2\pm i\sqrt{17}$
$x=\frac{-2\pm i\sqrt{17}}{2}$
$x=\boxed{\frac{-2\pm\sqrt{17}i}{2}}$

Solve the Equation by Using the Square Root Property (2x+2)2=−17( 2 x + 2 ) ^ { 2 } = - 17(2x+2)2=−17

Solve the Equation by Using the Square Root Property $( 2 x + 2 ) ^ { 2 } = - 17$