Factor the difference of cubes. $t ^ { 3 } - 8$
A) $( t + 2 ) \left( t ^ { 2 } - 2 t - 4 \right)$
B) $( t - 2 ) \left( t ^ { 2 } + 2 t + 4 \right)$
C) $( t - 2 ) \left( t ^ { 2 } - 2 t + 4 \right)$
D) $( t + 2 ) \left( t ^ { 2 } + 2 t + 4 \right)$
E) $( t + 2 ) \left( t ^ { 2 } - 2 t + 4 \right)$

Question

Quizplus · Accepted Answer

The difference of cubes formula is $a^3 - b^3 = (a - b)(a^2 + ab + b^2)$. Here, $t^3 - 8$ can be written as $t^3 - 2^3$, so it factors to $(t - 2)(t^2 + 2t + 4)$.

Factor the Difference of Cubes t3−8t ^ { 3 } - 8t3−8

Factor the Difference of Cubes $t ^ { 3 } - 8$