Factor a negative real number out of the polynomial $10 - y ^ { 2 }$ and then write the polynomial factor in standard form.
A) $10 - y ^ { 2 }$
B) $- \left( y ^ { 2 } - 10 \right)$
C) -($10 - y ^ { 2 }$ )
D) $y ^ { 2 } + 10$
E) -($y ^ { 2 } + 10$ )

Question

Factor a negative real number out of the polynomial $10 - y ^ { 2 }$ and then write the polynomial factor in standard form.
A) $10 - y ^ { 2 }$
B) $- \left( y ^ { 2 } - 10 \right)$
C) -($10 - y ^ { 2 }$  )
D) $y ^ { 2 } + 10$
E) -($y ^ { 2 } + 10$ )

Quizplus · Accepted Answer

To factor out a negative real number, we need to take out a factor of -1. So, we have:
$$10 - y^2 = -1\cdot(y^2-10)$$
Now, we can write the polynomial factor in standard form:
$$y^2-10 = -1(y^2-10)$$
or, equivalently,
$$-(y^2-10)$$

Factor a Negative Real Number Out of the Polynomial 10−y210 - y ^ { 2 }10−y2

Factor a Negative Real Number Out of the Polynomial $10 - y ^ { 2 }$