Solve by using the quadratic formula: $$z ^ { 2 } = 8 z + 36$$
A) $4 - 2 \sqrt { 13 } , 4 + 2 \sqrt { 13 }$
B) $- 4 - 14 \sqrt { 13 } , - 4 + 14 \sqrt { 13 }$
C) $- 2 \sqrt { 13 } , 2 \sqrt { 13 }$
D) $4 - 14 \sqrt { 13 } , - 4 + 3 \sqrt { 13 }$
E) $- 4 + 2 \sqrt { 13 } , - 4 - 2 \sqrt { 13 }$

Question

Quizplus · Accepted Answer

The quadratic equation is $z^2 - 8z - 36 = 0$. Using the quadratic formula $z = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ with $a = 1$, $b = -8$, and $c = -36$, we find the solutions to be $4 - 2\sqrt{13}$ and $4 + 2\sqrt{13}$.

Solve by Using the Quadratic Formula z2=8z+36z ^ { 2 } = 8 z + 36z2=8z+36

Solve by Using the Quadratic Formula $z ^ { 2 } = 8 z + 36$