Solve by using the quadratic formula: $$x ^ { 2 } - 4 x + 3 = 0$$
A) 1, 3
B) 1, 5
C) -3, 3
D) 1, -2
E) No real number solution

Question

Quizplus · Accepted Answer

The quadratic formula is $$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$ for a quadratic equation $ax^2 + bx + c = 0$. Here, $a = 1$, $b = -4$, and $c = 3$. Plugging these into the formula gives $$x = \frac{4 \pm \sqrt{(-4)^2 - 4 \cdot 1 \cdot 3}}{2 \cdot 1} = \frac{4 \pm \sqrt{16 - 12}}{2} = \frac{4 \pm \sqrt{4}}{2} = \frac{4 \pm 2}{2}$$, which results in $x = 3$ or $x = 1$.

Solve by Using the Quadratic Formula x2−4x+3=0x ^ { 2 } - 4 x + 3 = 0x2−4x+3=0

Solve by Using the Quadratic Formula $x ^ { 2 } - 4 x + 3 = 0$