Question 1

Use the formulas for the hydraulic press to find the following value: r _l = 18 in. and r _s = 3 in. Find MA.

Accepted Answer

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Question 2

Use the scale drawing of a metal plate cover in a figure below to answer the question.
What is the distance between the centers of the right pair of circular holes? Give the answer to one decimal place.  Side of square = 0.1 cm
width = __________ cm

Accepted Answer

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Question 3

Use the formulas for the hydraulic press to find F _l . F _s = 10 lb, r _l = 6 in. and r _s = 2 in.

Accepted Answer

The formula for a hydraulic press is F_l / F_s = (r_l / r_s)^2. Substituting the given values: F_l / 10 = (6 / 2)^2 = 9. Solving for F_l gives F_l = 90 lb.

Question 4

F _l = 3,000 lb and $M A = \frac { 75 } { 1 }$ . Find F _s .

Accepted Answer

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Question 5

Use the formulas for the hydraulic press to find MA. r _l = 54 in. and r _s = 6 in. MA = __________

Accepted Answer

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Question 6

A 150-lb force is applied to the small piston of a hydraulic press produces a 3,000-lb force by the large piston. Find its mechanical advantage.

Accepted Answer

The mechanical advantage (MA) of a hydraulic press is calculated by dividing the output force by the input force. In this case, MA = 3000 lb / 150 lb = 20. Therefore, the mechanical advantage is $\frac { 20 } { 1 }$.

Question 7

Use the scale drawing of a metal plate cover in the figure below to answer the question. What is the area of the plate cover?  Side of square = 0.8 cm

Accepted Answer

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Question 8

Use the formulas for the hydraulic press to find F _s . F _l = 800 lb, r _l = 10 in. and r _s = 5 in.

Accepted Answer

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Question 9

Use the formulas for the hydraulic press to find F _l . F _s = 21 lb, r _l = 8 in. and r _s = 1 in.

Accepted Answer

The formula for a hydraulic press is $F_1/F_2 = r_2^2 / r_1^2$, where $F_1$ and $F_2$ are the forces applied on the small and large pistons, respectively, and $r_1$ and $r_2$ are the radii of the small and large pistons, respectively. Given $F_1 = 21$ lb, $r_1 = 1$ in, and $r_2 = 8$ in, we can rearrange the formula to solve for $F_2$: $F_2 = F_1 \times (r_2^2 / r_1^2)$. Plugging in the given values, $F_2 = 21 \times (8^2 / 1^2) = 21 \times 64 = 1344$ lb.

Question 10

$F _ { 1 } = 6,160$ and $M A = \frac { 70 } { 1 }$ . Find $F _ { 1 }$ .

Accepted Answer

Using the formula $F _ { 1 } = M A \times F _ { 2 }$, we can solve for $F_2$ as follows:
$$F _ { 1 } = 6,160, \quad MA = 70, \quad F_2 = ?$$
$$F _ { 1 } = M A \times F _ { 2 } \rightarrow F _ { 2 } = \frac { F _ { 1 } } { M A } = \frac { 6,\!160 } { 70 } \approx 88 \text{ lb}$$
Therefore, the answer is B, 88 lb.

Question 11

Use the formulas for the hydraulic press to solve the following problem. A force of 1,725 lb is exerted by a piston of radius 15 in. of a hydraulic press. What force was applied to its piston of radius 3 in.?

Accepted Answer

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Question 12

Use the formulas for the hydraulic press to solve the following problem. A force of 50 lb is applied to a piston of radius 9 in. of a hydraulic press. The large piston has a radius of 18 in. What force is exerted by the large piston?

Accepted Answer

The force exerted by the large piston is 200 lb because the pressure is the same throughout the hydraulic press. The pressure is calculated by dividing the force applied to the small piston by the area of the small piston. The area of the large piston is four times the area of the small piston, so the force exerted by the large piston is four times the force applied to the small piston.

Question 13

Use the formulas for the hydraulic press to find F _l . F _s = 52 lb, r _l = 9 in. and r _s = 1 in.

Accepted Answer

The formula for the hydraulic press is:

F S1U1B1/F S1U1B0 = A S1U1B0/A S1U1B1

Where,
F S1U1B1 = Force applied to small piston (known)
F S1U1B0 = Force applied to large piston (unknown)
A S1U1B0 = Area of large piston (known)
A S1U1B1 = Area of small piston (known)

Also, we have the formula:

A S1U1B1/A S1U1B0 = (r S1U1B0)^2/(r S1U1B1)^2

Where,
r S1U1B1 = radius of small piston (known)
r S1U1B0 = radius of large piston (known)

Multiplying these two equations, we get:

F S1U1B1/F S1U1B0 = (r S1U1B0/r S1U1B1)^2

Substituting the given values, we get:

52/F S1U1B0 = (9/1)^2

Solving for F S1U1B0, we get:

F S1U1B0 = 4,212 lb

Therefore, the answer is B.

Question 14

Use the formulas for the hydraulic press to find F _s . F _l = 2,400 lb, r _l = 4 in. and r _s = 2 in.

Accepted Answer

F _s = (F _l * r _l ) / r _s = (2,400 lb * 4 in.) / 2 in. = 4,800 lb / 2 in. = 2,400 lb

Question 15

Use the formulas for the hydraulic press to find MA. r _l = 48 in. and r _s = 4 in. MA = __________

Accepted Answer

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Question 16

Use the formulas for the hydraulic press to find MA. r _l = 20 in. and r _s = 4 in.

Accepted Answer

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Quiz 7: Ratio and Proportion

Use the formulas for the hydraulic press to find the following value: r l = 18 in. and r s = 3 in. Find MA.

Use the scale drawing of a metal plate cover in a figure below to answer the question. What is the distance between the centers of the right pair of circular holes? Give the answer to one decimal place. Side of square = 0.1 cm width = __________ cm

Use the formulas for the hydraulic press to find F l . F s = 10 lb, r l = 6 in. and r s = 2 in.

F l = 3,000 lb and MA=751M A = \frac { 75 } { 1 }MA=175​ . Find F s .

Use the formulas for the hydraulic press to find MA. r l = 54 in. and r s = 6 in. MA = __________

A 150-lb force is applied to the small piston of a hydraulic press produces a 3,000-lb force by the large piston. Find its mechanical advantage.

Use the scale drawing of a metal plate cover in the figure below to answer the question. What is the area of the plate cover? Side of square = 0.8 cm

Use the formulas for the hydraulic press to find F s . F l = 800 lb, r l = 10 in. and r s = 5 in.

Use the formulas for the hydraulic press to find F l . F s = 21 lb, r l = 8 in. and r s = 1 in.

F1=6,160F _ { 1 } = 6,160F1​=6,160 and MA=701M A = \frac { 70 } { 1 }MA=170​ . Find F1F _ { 1 }F1​ .

Use the formulas for the hydraulic press to solve the following problem. A force of 1,725 lb is exerted by a piston of radius 15 in. of a hydraulic press. What force was applied to its piston of radius 3 in.?

Use the formulas for the hydraulic press to solve the following problem. A force of 50 lb is applied to a piston of radius 9 in. of a hydraulic press. The large piston has a radius of 18 in. What force is exerted by the large piston?

Use the formulas for the hydraulic press to find F l . F s = 52 lb, r l = 9 in. and r s = 1 in.

Use the formulas for the hydraulic press to find F s . F l = 2,400 lb, r l = 4 in. and r s = 2 in.

Use the formulas for the hydraulic press to find MA. r l = 48 in. and r s = 4 in. MA = __________

Use the formulas for the hydraulic press to find MA. r l = 20 in. and r s = 4 in.

Use the formulas for the hydraulic press to find the following value: r _l = 18 in. and r _s = 3 in. Find MA.

Use the formulas for the hydraulic press to find F _l . F _s = 10 lb, r _l = 6 in. and r _s = 2 in.

F _l = 3,000 lb and $M A = \frac { 75 } { 1 }$ . Find F _s .

Use the formulas for the hydraulic press to find MA. r _l = 54 in. and r _s = 6 in. MA = __________

Use the formulas for the hydraulic press to find F _s . F _l = 800 lb, r _l = 10 in. and r _s = 5 in.

Use the formulas for the hydraulic press to find F _l . F _s = 21 lb, r _l = 8 in. and r _s = 1 in.

$F _ { 1 } = 6,160$ and $M A = \frac { 70 } { 1 }$ . Find $F _ { 1 }$ .

Use the formulas for the hydraulic press to find F _l . F _s = 52 lb, r _l = 9 in. and r _s = 1 in.

Use the formulas for the hydraulic press to find F _s . F _l = 2,400 lb, r _l = 4 in. and r _s = 2 in.

Use the formulas for the hydraulic press to find MA. r _l = 48 in. and r _s = 4 in. MA = __________

Use the formulas for the hydraulic press to find MA. r _l = 20 in. and r _s = 4 in.