Solve by the quadratic formula: $x ^ { 2 } = 4 x - 2$
A) $\{ 2 \pm \sqrt { 2 } \}$
B) $\{ 2 \pm 2 \sqrt { 2 } \}$
C) $\{ 2 \pm i \sqrt { 2 } \}$
D) $\{ 2 \pm 2 i \sqrt { 2 } \}$

Question

Quizplus · Accepted Answer

First, rearrange the equation to standard form: $x^2 - 4x + 2 = 0$. Then, apply the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, with $a = 1$, $b = -4$, and $c = 2$. This gives $x = \frac{4 \pm \sqrt{(-4)^2 - 4(1)(2)}}{2(1)} = \frac{4 \pm \sqrt{16 - 8}}{2} = \frac{4 \pm \sqrt{8}}{2} = 2 \pm \sqrt{2}$.

Solve by the Quadratic Formula x2=4x−2x ^ { 2 } = 4 x - 2x2=4x−2

Solve by the Quadratic Formula $x ^ { 2 } = 4 x - 2$