The solutions of $a x ^ { 2 } + b x + c = 0$ $( a \neq 0 )$ are
A) $x = - b \pm \frac { \sqrt { b ^ { 2 } - 4 a c } } { 2 a }$
B) $x = \frac { - b \pm \sqrt { b ^ { 2 } - 4 a c } } { 2 a }$
C) $x = \frac { \pm b \sqrt { b ^ { 2 } - 4 a c } } { 2 a }$
D) $x = \frac { b \pm \sqrt { b ^ { 2 } - 4 a c } } { 2 a }$

Question

The solutions of $a x ^ { 2 } + b x + c = 0$  $( a \neq 0 )$ are
A) $x = - b \pm \frac { \sqrt { b ^ { 2 } - 4 a c } } { 2 a }$
B) $x = \frac { - b \pm \sqrt { b ^ { 2 } - 4 a c } } { 2 a }$
C) $x = \frac { \pm b \sqrt { b ^ { 2 } - 4 a c } } { 2 a }$
D) $x = \frac { b \pm \sqrt { b ^ { 2 } - 4 a c } } { 2 a }$

Quizplus · Accepted Answer

The correct solution for a quadratic equation $ax^2 + bx + c = 0$ is given by the quadratic formula: $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, which matches choice B.

The Solutions Of ax2+bx+c=0a x ^ { 2 } + b x + c = 0ax2+bx+c=0

The Solutions Of $a x ^ { 2 } + b x + c = 0$