Solve $( x + 1 ) ^ { 2 } - 7 = 0$ by square root property.
A) $\{ - 1 \pm 4 \sqrt { 5 } \}$
B) $\{ 1 \pm 4 \sqrt { 5 } \}$
C) $\{ 1 \pm \sqrt { 7 } \}$
D) $\{ - 1 \pm \sqrt { 7 } \}$

Question

Quizplus · Accepted Answer

First, isolate the squared term: $(x + 1)^2 = 7$. Then, take the square root of both sides: $x + 1 = \pm \sqrt{7}$. Finally, solve for $x$ by subtracting 1 from both sides: $x = -1 \pm \sqrt{7}$.

Solve (x+1)2−7=0( x + 1 ) ^ { 2 } - 7 = 0(x+1)2−7=0

Solve $( x + 1 ) ^ { 2 } - 7 = 0$