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Question 5
Solve 2x2−9=02 x ^ { 2 } - 9 = 02x2−9=0 by the square root property.
A) {92}\left\{ \frac { 9 } { 2 } \right\}{29} B) {±3}\{ \pm 3 \}{±3} C) {±322}\left\{ \pm \frac { 3 \sqrt { 2 } } { 2 } \right\}{±232} D) {−3}\{ - 3 \}{−3}
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Q4: Solve Q6: What number is added to eachQ7: What is the next step inQ8: Solve Q9: When we add 9 to Q10: Solve Q11: Solve by square root property: Unlock this Answer For Free Now!View this answer and more for free by performing one of the following actionsScan the QR code to install the App and get 2 free unlocksMaximize QR codeUnlock quizzes for free by uploading documentsUpload documents
Q6: What number is added to each
Q7: What is the next step in
Q8: Solve Q9: When we add 9 to Q10: Solve Q11: Solve by square root property:
Q9: When we add 9 to
Q10: Solve Q11: Solve by square root property:
Q11: Solve by square root property:
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