Solve the problem.
-If the voltage, V, in an electric circuit is held constant, then the current, I, is inversely proportional to the resistance, R. If the current is 160 milliamperes (mA) when the resistance is 2 ohms, find the current when the
Resistance is 8 ohms.
A) 636 mA
B) 80 mA
C) 640 mA
D) 40 mA

Question

Quizplus · Accepted Answer

Using the formula for inverse proportionality, I1*R1 = I2*R2, where I1 = 160 mA, R1 = 2 ohms, and R2 = 8 ohms:
160*2 = I2*8
Simplifying and solving for I2:
I2 = 40 mA According to the problem, I is inversely proportional to R. This can be expressed as follows:

I = k/R

where k is a constant of proportionality.

To find k, we can use the given values of I and R:

160 mA = k/2 ohms

k = 320 mA*ohms

Now we can use the value of k to find I when R = 8 ohms:

I = k/R = (320 mA*ohms)/8 ohms = 40 mA

Therefore, the answer is D) 40 mA.

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