Solve the problem.
-For a resistor in a direct current circuit that does not vary its resistance, the power that a resistor must dissipate is directly proportional to the square of the voltage across the resistor. The resistor must dissipate watt of
Power when the voltage across the resistor is 13 volts. Find the power that the resistor must dissipate when the
Voltage across it is 26 volts.
A) s

Question

Solve the problem.
-For a resistor in a direct current circuit that does not vary its resistance, the power that a resistor must dissipate is directly proportional to the square of the voltage across the resistor. The resistor must dissipate  watt of
Power when the voltage across the resistor is 13 volts. Find the power that the resistor must dissipate when the
Voltage across it is 26 volts.
A) s

Quizplus · Accepted Answer

Since power is directly proportional to the square of voltage, we can use the formula P=kV^2, where k is a constant of proportionality. We can find k by using the given information: P=11ebb63d_1b62_ebbd_b851_3d4be5d0f008_TB8475_11 and V=13. Thus, k=P/V^2=11ebb63d_1b63_12cf_b851_d74944ccc525_TB8475_11. To find the power when V=26, we plug in these values into the formula: P=kV^2=11ebb63d_1b63_12d1_b851_ad209c4c1108_TB8475_11. Therefore, the answer is D. Since the power is directly proportional to the square of the voltage, we can use the equation P=kV^2, where P is the power, V is the voltage, and k is the constant of proportionality. We can solve for k by using the given information:

11ebb63d_1b62_ebbd_b851_3d4be5d0f008_TB8475_11 = k(13)^2

Solving for k, we get:

k = 11ebb63d_1b62_ebbd_b851_3d4be5d0f008_TB8475_11 / 169

Now we can use this value of k to find the power when the voltage is 26:

P = k(26)^2 = 11ebb63d_1b63_12d1_b851_ad209c4c1108_TB8475_11

Therefore, the answer is D.

Solve the Problem. -For a Resistor in a Direct Current Circuit That Does