Question 1

The critical chi-square value for 15 degrees of freedom when  and the test is right-tailed is 19.675.

Accepted Answer

The critical chi-square value for 15 degrees of freedom when the test is right-tailed and the significance level is 0.05 is 24.996. Therefore, the statement is false. The critical chi-square value for 15 degrees of freedom when the test is right-tailed is 24.996.

Question 2

Before computing the test value, one must state the hypothesis.

Accepted Answer

Stating the hypothesis is a crucial step in the hypothesis testing process. Without a clear and specified hypothesis, it would be impossible to determine whether the results are statistically significant or not.

Question 3

For two degrees of freedom, the value of a shown in the figure below is 0.05.

Accepted Answer

The figure is not provided, but if the value of a is given as 0.05 for a system with two degrees of freedom, it is likely referring to the significance level of a statistical test. A value of 0.05 indicates that there is a 5% chance of observing a result as extreme or more extreme than the one observed, assuming the null hypothesis is true. This is a commonly used threshold for determining statistical significance. The figure mentioned in the question is missing, but if a two-degree-of-freedom system has a significance level (alpha) of 0.05, it means that the level of confidence is 95%. This is commonly used in statistical hypothesis testing to determine if there is a significant difference between two groups or sets of data.

Question 4

An anatomy teacher hypothesizes that the final grades in her class are distributed as 10% A's, 23% B's, 45% C's, 14% D's, and 8% F's.What is the critical value if at the end of the semester she has the
Following grades? Use  . 
A)9.236
B)7.779
C)11.070
D)9.488

Accepted Answer

The answer of An anatomy teacher hypothesizes that the final...

Question 5

What is the null hypothesis?
A)Children spend the same amount of time watching TV each day.
B)Children spend different amounts of time watching TV each day.
C)Children spend more time watching TV on weekends.
D)Children spend less than 2.6 hours a day watching TV.

Accepted Answer

The null hypothesis in this case would be that there is no difference in the amount of time children spend watching TV each day. This is the baseline assumption that will be tested against any alternative hypotheses that suggest there is a significant difference.

Question 6

The null hypothesis should not be rejected for the data given in the figure
below.

Accepted Answer

Without seeing the figure, it is impossible to make a definitive statement. However, if the data analysis and appropriate statistical tests have been conducted and lead to the decision that the null hypothesis should not be rejected, then the answer would be True. Without any further information or context it is not possible to determine if the null hypothesis should be rejected or not. Therefore, based solely on the information given in the figure, the null hypothesis should not be rejected cannot be determined, so the answer is A.

Question 7

The test of homogeneity of proportions is used to determine whether the proportions for a variable are
unequal when several samples are selected from different populations.

Accepted Answer

The answer of The test of homogeneity of proportions is...

Question 8

The test of independence of variables is used to determine whether two variables are independent of or
related to each other when a single sample is selected.

Accepted Answer

The statement is true. The test of independence of variables is indeed used to determine the relationship between two variables when a single sample is selected.

Question 9

What is the expected value?
A)112
B)247
C)120
D)171

Accepted Answer

The answer of What is the expected value?
A)112
B)247
C)120
D)171...

Question 10

The chi-square goodness-of-fit test is always one-tailed left.

Accepted Answer

The chi-square goodness-of-fit test can be one-tailed left, one-tailed right, or two-tailed depending on the research question and hypothesis being tested.

Question 11

Frequencies obtained by calculation are called expected frequencies.

Accepted Answer

Expected frequencies are calculated based on probability and the characteristics of the distribution, and represent what we would expect to see if the distribution followed a certain pattern.

Question 12

The chi-square independence test can be used to test the independence of two variables.

Accepted Answer

The chi-square independence test is specifically used to test the independence of two variables.

Question 13

What is the test value?
A)2.82
B)100
C)72.12
D)33.78

Accepted Answer

The answer of What is the test value?
A)2.82
B)100
C)72.12
D)33.78...

Question 14

What is the critical value?
A)18.475
B)16.812
C)12.592
D)14.067

Accepted Answer

The answer of What is the critical value?
A)18.475
B)16.812
C)12.592
D)14.067...

Question 15

In a chi-square goodness-of-fit test, when there is close agreement between the observed frequency and
the expected frequency, the chi-square test value will be small.

Accepted Answer

This is true. When there is close agreement between the observed and expected frequencies, the differences between the observed and expected frequencies will be small, resulting in a small chi-square test value.

Question 16

A manager of a health club believes that 32% of the members joined his club in the winter, 24% joined in
the spring, 20% joined in the summer, and 24% joined in the fall.The number of memberships this year
shows that 110 joined in the winter, 70 joined in the spring, 60 in the summer, and 68 in the fall.The test
value for this scenario would be 2.05.

Accepted Answer

The answer of A manager of a health club believes...

Question 17

A contingency table is designated as  (columns times rows) table.

Accepted Answer

A contingency table is typically designated with the number of rows and columns, not a random string of characters and numbers. A contingency table is typically designated as rows times columns, not columns times rows.

Question 18

The degrees of freedom for a  contingency table would be 24.

Accepted Answer

The answer of The degrees of freedom for a ...

Question 19

In a goodness-of-fit test, the degrees of freedom are equal to the number of categories minus two.

Accepted Answer

In a goodness-of-fit test, the degrees of freedom are equal to the number of categories minus one.

Question 20

The computational procedure for homogeneity of proportions differs from that of the test of independence
in that it takes into account the standard deviation.
A sociologist wanted to determine whether there was a difference in the amount of time children aged 5-
7 spent watching television each day.Check the following data for evidence that the number of minutes
spent watching television is equally distributed throughout the week.The data is shown graphically in
Figure 11-1.Use

Accepted Answer

The question is asking about homogeneity of proportions, but the data provided is only showing the distribution of minutes spent watching TV each day. The question is not clear on whether the data represents different groups or categories, so it is not possible to determine if a test for homogeneity of proportions is appropriate. Additionally, the question does not provide any information about the standard deviation, which would be necessary for conducting a test for homogeneity of proportions. Therefore, the statement is false. The question is asking about homogeneity of proportions, which is a test for whether the proportions in different groups are the same. The given data only shows the average minutes of television watched per day, but it doesn't show the proportions of children who watch different amounts of television. Therefore, we cannot use the homogeneity of proportions test for this data.

Quiz 11: Other Chi-Square Tests

The critical chi-square value for 15 degrees of freedom when and the test is right-tailed is 19.675.

Before computing the test value, one must state the hypothesis.

For two degrees of freedom, the value of a shown in the figure below is 0.05.

An anatomy teacher hypothesizes that the final grades in her class are distributed as 10% A's, 23% B's, 45% C's, 14% D's, and 8% F's.What is the critical value if at the end of the semester she has the Following grades? Use .

What is the null hypothesis?

The null hypothesis should not be rejected for the data given in the figure below.

The test of homogeneity of proportions is used to determine whether the proportions for a variable are unequal when several samples are selected from different populations.

The test of independence of variables is used to determine whether two variables are independent of or related to each other when a single sample is selected.

What is the expected value?

The chi-square goodness-of-fit test is always one-tailed left.

Frequencies obtained by calculation are called expected frequencies.

The chi-square independence test can be used to test the independence of two variables.

What is the test value?

What is the critical value?

In a chi-square goodness-of-fit test, when there is close agreement between the observed frequency and the expected frequency, the chi-square test value will be small.

A contingency table is designated as (columns times rows) table.

The degrees of freedom for a contingency table would be 24.

In a goodness-of-fit test, the degrees of freedom are equal to the number of categories minus two.