Find the x-intercepts of the function.
-$f ( x ) = \left( x + \frac { 1 } { 5 } \right) ^ { 2 } ( x + 9 ) ^ { 5 }$
A) $x \text {-intercept: } \left( - \frac { 1 } { 5 } , 0 \right) , x \text {-intercept: } ( 9,0 )$
B) $x \text {-intercept: } \left( \frac { 1 } { 5 } , 0 \right) , x \text {-intercept: } ( - 9,0 )$
C) $x \text {-intercept: } \left( \frac { 1 } { 5 } , 0 \right) , x \text {-intercept: } ( 9,0 )$
D) $\mathrm { x } \text {-intercept: } \left( - \frac { 1 } { 5 } , 0 \right) , \mathrm { x } \text {-intercept: } ( - 9,0 )$

Question

Quizplus · Accepted Answer

The x-intercepts of a function occur where the function equals zero. For $f(x) = \left( x + \frac{1}{5} \right)^2 (x + 9)^5$, setting $f(x) = 0$ gives the roots $x = -\frac{1}{5}$ and $x = -9$, corresponding to the intercepts $\left( -\frac{1}{5}, 0 \right)$ and $(-9, 0)$.

Find the X-Intercepts of the Function f(x)=(x+15)2(x+9)5f ( x ) = \left( x + \frac { 1 } { 5 } \right) ^ { 2 } ( x + 9 ) ^ { 5 }f(x)=(x+51​)2(x+9)5

Find the X-Intercepts of the Function $f ( x ) = \left( x + \frac { 1 } { 5 } \right) ^ { 2 } ( x + 9 ) ^ { 5 }$