Find the real zeros of the function, state their multiplicities if it is a number other than 1.
-$f ( x ) = ( x + 1 ) ( x - 4 ) \left( x ^ { 2 } - 4 \right)$
A) $\begin{array} { l }
x = - 1 , x = 4 \
x = 2 , \text { multiplicity: } 2
\end{array}$
B) $\begin{array} { l }
x = - 1 , x = 4 \
x = 2 , x = - 2
\end{array}$
C) $\begin{array} { l }
x = 1 , x = - 4 \
x = 2 , x = - 2
\end{array}$
D) $\mathrm { x } = 0$, multiplicity: 2
$\mathrm { x } = 2$, multiplicity: 2

Question

Find the real zeros of the function, state their multiplicities if it is a number other than 1.
-$f ( x ) = ( x + 1 ) ( x - 4 ) \left( x ^ { 2 } - 4 \right)$ 
A) $\begin{array} { l } 
x = - 1 , x = 4 \
x = 2 , \text { multiplicity: } 2
\end{array}$
B) $\begin{array} { l } 
x = - 1 , x = 4 \
x = 2 , x = - 2
\end{array}$
C) $\begin{array} { l } 
x = 1 , x = - 4 \
x = 2 , x = - 2
\end{array}$
D) $\mathrm { x } = 0$, multiplicity: 2
$\mathrm { x } = 2$, multiplicity: 2

Quizplus · Accepted Answer

The given function $f(x) = (x + 1)(x - 4)(x^2 - 4)$ can be factored further as $f(x) = (x + 1)(x - 4)(x - 2)(x + 2)$. This shows the real zeros are $x = -1$, $x = 4$, $x = 2$, and $x = -2$, each with multiplicity 1.

Find the Real Zeros of the Function, State Their Multiplicities f(x)=(x+1)(x−4)(x2−4)f ( x ) = ( x + 1 ) ( x - 4 ) \left( x ^ { 2 } - 4 \right)f(x)=(x+1)(x−4)(x2−4)

Find the Real Zeros of the Function, State Their Multiplicities $f ( x ) = ( x + 1 ) ( x - 4 ) \left( x ^ { 2 } - 4 \right)$