Solve the inequality and give the solution in interval notation.
-$$\frac { ( x + 12 ) ( x - 2 ) } { x - 1 } \geq 0$$
A) $$[ - 12,1 ) \cup [ 2 , \infty )$$
B) $$( - \infty , - 12 ] \cup [ 2 , \infty )$$
C) $$( - \infty , - 12 ] \cup ( 1,2 ]$$
D) $$[ - 12,1 ) \cup ( 1,2 ]$$

Question

Quizplus · Accepted Answer

To solve the inequality $\frac { ( x + 12 ) ( x - 2 ) } { x - 1 } \geq 0$, we find the zeros of the numerator and the undefined points of the denominator. The zeros of the numerator are $x = -12$ and $x = 2$, and the denominator is undefined at $x = 1$. Plotting these points on a number line and testing intervals gives us the solution $[ - 12,1 ) \cup [ 2 , \infty )$.

Solve the Inequality and Give the Solution in Interval Notation (x+12)(x−2)x−1≥0\frac { ( x + 12 ) ( x - 2 ) } { x - 1 } \geq 0x−1(x+12)(x−2)​≥0

Solve the Inequality and Give the Solution in Interval Notation $\frac { ( x + 12 ) ( x - 2 ) } { x - 1 } \geq 0$