Solve the inequality and give the solution in interval notation.
-$$\frac { ( x - 6 ) ( x + 6 ) } { x } \leq 0$$
A) $$[ - 6,0 ) \cup ( 0,6 ]$$
B) $$[ - 6,0 ) \cup [ 6 , \infty )$$
C) $$( - \infty , - 6 ] \cup [ 6 , \infty )$$
D) $$( - \infty , - 6 ] \cup ( 0,6 ]$$

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The Answer of Solve the inequality and give the solution in interval notation.
-$$\frac { ( x - 6 ) ( x + 6 ) } { x } \leq 0$$
A) $$[ - 6,0 ) \cup ( 0,6 ]$$
B) $$[ - 6,0 ) \cup [ 6 , \infty )$$
C) $$( - \infty , - 6 ] \cup [ 6 , \infty )$$
D) $$( - \infty , - 6 ] \cup ( 0,6 ]$$

Solve the Inequality and Give the Solution in Interval Notation (x−6)(x+6)x≤0\frac { ( x - 6 ) ( x + 6 ) } { x } \leq 0x(x−6)(x+6)​≤0

Solve the Inequality and Give the Solution in Interval Notation $\frac { ( x - 6 ) ( x + 6 ) } { x } \leq 0$