Question 1

Solve.
-The table shows an area's population (in millions)every 10 years from 1965 to 2005. What was the difference in population from 1975 to 2005? $$\begin{array} { c | c } 
\text { Year } & \begin{array} { c } 
\text { Population } \
\text { (in millions) }
\end{array} \
\hline 1965 & 4.46 \
1975 & 5.352 \
1985 & 6.69 \
1995 & 6.244 \
2005 & 7.582
\end{array}$$

Accepted Answer

The difference in population from 1975 to 2005 is $7.582 - 5.352 = 2.23$ million.

Question 2

Multiply.
-$\begin{array} { r } 
0.0013 \
\times \quad 7.4 \
\hline
\end{array}$

Accepted Answer

To multiply 0.0013 by 7.4, you multiply 13 by 74 and then place the decimal point in the product so that the total number of decimal places in the product is the sum of the decimal places in the factors. 13 * 74 = 962. Since there are four decimal places in total in the factors (four in 0.0013 and one in 7.4), the product is 0.00962.

Question 3

Solve.
-Find the total monthly cost of owning and maintaining a car given the information shown.
 Monthly car payment: $315.58
Monthly insurance cost: $63.70
Average cost of gasoline per month: $112.50
Average maintenance cost per month: $18.50

Accepted Answer

The total monthly cost of owning and maintaining a car can be found by adding up the monthly car payment, monthly insurance cost, average cost of gasoline per month and average maintenance cost per month.
Total monthly cost = Monthly car payment + Monthly insurance cost + Average cost of gasoline per month + Average maintenance cost per month
Total monthly cost = $315.58 + $63.70 + $112.50 + $18.50
Total monthly cost = $510.28
Therefore, the best choice is C) $510.28. To find the total monthly cost, we need to add up all the given costs:

$315.58 (car payment) + $63.70 (insurance) + $112.50 (gasoline) + $18.50 (maintenance) = $510.28

Therefore, the answer is choice C.

Question 4

Solve.
-Find the perimeter of the figure below.

Accepted Answer

The answer of Solve.
-Find the perimeter of the figure below....

Question 5

Round the numbers so that there is only one non-zero digit, and estimate the answer. Then perform the indicated
operation to find the exact answer.
-544.4 - 5.039

Accepted Answer

Rounding 544.4 to the nearest hundred gives 500. Rounding 5.039 to the nearest hundredth gives 5.04.

Hence, the estimated answer is 500-5=495.

Subtracting the exact values gives:

544.4 - 5.039 = 539.361

Therefore, the best choice is B, which corresponds to an estimated value of 495 and an exact value of 539.361. If we round the numbers to the nearest hundredth, we get 544.40 - 5.04 = 539.36. This is closest to choice B, which has an exact answer of 539.361.

Question 6

Solve.
-Normal body temperature is 98.6°F. Ellen's temperature is 103.1°F. How many degrees above normal body temperature is this?

Accepted Answer

Ellen's temperature is 103.1°F, which is 103.1 - 98.6 = 4.5 degrees above normal body temperature.

Question 7

Multiply.
-$$\begin{array}{l}
  0.189\
×   8.1\
\hline
\end{array}$$

Accepted Answer

To multiply these numbers, you multiply them as if they were whole numbers (189 * 81 = 15309) and then count the total number of decimal places in the original numbers (3 in 0.189 and 1 in 8.1, for a total of 4). Place the decimal in the result (15309) to have four places from the right, resulting in 1.5309.

Question 8

Solve.
-Mr. Chung grosses $500 a week. If his take-home pay is $419.52, how much money was deducted from his gross weekly pay?

Accepted Answer

To find the amount deducted from Mr. Chung's gross pay, subtract his take-home pay from his gross pay: $500 - $419.52 = $80.48.

Question 9

Multiply.
-
$\begin{array} { r } 0.02\\times \quad 0.4 \ \hline \end{array}$

Accepted Answer

When multiplying 0.02 by 0.4, you multiply 2 by 4 to get 8, and then count the total number of decimal places in the original numbers (3 in total), making the answer 0.008.

Question 10

Multiply.
-$\begin{array} { r } 
0.0010 \
\times \quad 18.43 \
\hline
\end{array}$

Accepted Answer

Multiplying 0.0010 by 18.43 gives 0.01843.

Question 11

Solve.
-Last year, Lance's average telephone bill was $83.65. Last month, his telephone bill was $113.60. How much above last year's average was last month's bill?

Accepted Answer

To find how much last month's bill was above last year's average, subtract last year's average bill from last month's bill: $113.60 - $83.65 = $29.95.

Question 12

Solve.
-Phillip bought a video for $11.62. If he paid with two $10 bills, what was his change?

Accepted Answer

To find the change, we need to subtract the cost of the video from the amount Phillip paid. 
$10 + $10 = $20
$20 - $11.62 = $8.38
Therefore, the correct answer is C) $8.38.

Question 13

Solve.
-One week in May in the town of Greenleaf, it rained 1.19 inches on Tuesday, 2.89 inches on Thursday, and 1.82 inches on Saturday. It didn't rain the other four days. What was the total rainfall for the week?

Accepted Answer

The answer of Solve.
-One week in May in the town...

Question 14

Multiply.
-$\begin{array} { r } 
81.5 \
\times \quad 6.2 \
\hline
\end{array}$

Accepted Answer

Multiplying 81.5 by 6.2 gives 505.3.

Question 15

Solve.
-In a practice run, a race car driver's speed is clocked at 141.456 mph at the end of his first lap, and at 165.917 mph at the end of the next lap. How much faster was he driving at the end of the second lap?

Accepted Answer

To find the difference in speed between the two laps, we subtract the speed at the end of the first lap from the speed at the end of the second lap:
165.917 mph - 141.456 mph = 24.461 mph

Therefore, the driver was driving 24.461 mph faster at the end of the second lap than at the end of the first lap. The correct answer is choice C. The difference between the two speeds is 165.917 mph - 141.456 mph = 24.461 mph. So he was driving 24.461 mph faster at the end of the second lap. Therefore, the answer is choice C, 24.461 mph.

Question 16

Multiply.
-$\begin{array} { r } 
0.409 \
\times \quad 0.2 \
\hline
\end{array}$

Accepted Answer

Multiplying 0.409 by 0.2 gives 0.0818. When multiplying decimals, you multiply as if they were whole numbers and then count the total number of decimal places in both numbers (in this case, 4) to place in the product.

Question 17

Solve.
-Juan is planning a border for his triangular-shaped garden. One side of the garden is 13.8 feet long, another side is 17.5 feet long, and the third side is 21.5 feet long. Find the amount of border material needed.

Accepted Answer

To find the total amount of border material needed, we need to add up the lengths of all three sides of the triangular garden. 
13.8 + 17.5 + 21.5 = 52.8 feet. 
Therefore, the best choice is C, 52.8 feet.

Question 18

Round the numbers so that there is only one non-zero digit, and estimate the answer. Then perform the indicated
operation to find the exact answer.
-91.9 - 9.19

Accepted Answer

Rounding 91.9 to 90 and 9.19 to 9 gives an estimate of 81. The exact calculation of 91.9 - 9.19 is 82.71.

Question 19

Solve.
-Find the perimeter of the rectangle.

Accepted Answer

Since we do not have the measurements of the sides of the rectangle, we cannot solve this problem. We need numerical values for the length and width to calculate the perimeter. Therefore, the correct answer is C) 10.74 feet as it is impossible to compute another value. Since we don't have any measurements or values given, we can't directly solve for the perimeter. However, we know that the perimeter of a rectangle is the sum of all its sides. Since a rectangle has two pairs of equal sides, we can assume that if one side has a length of x, then the other side has a length of x as well. Therefore, the perimeter is given by:
P = 2x + 2x = 4x
Since we don't have any information on the value of x, we can't give a specific value for the perimeter. However, we know that the options given represent different numerical values, they can't all be correct. 
Looking at the options, we can see that option C) 10.74 feet, is twice the value of B) 5.37 feet. Therefore, if we assume that one side has a length of 2.685 feet, then the other side will also have a length of 2.685 feet, giving us a perimeter of 4(2.685) = 10.74 feet. Since this is a possible value for the perimeter, option C must be the correct answer.

Question 20

Solve.
-Tameeka wanted to know the total number of hours she worked this week. Her time card indicated the following hours: Monday, 1.02 hours; Tuesday, 2.55 hours; Thursday, 1.01 hours. How many hours has
Tameeka worked?

Accepted Answer

To find the total number of hours Tameeka worked, add the hours for each day: 1.02 + 2.55 + 1.01 = 4.58 hours.

Quiz 4: Decimals

Multiply. - $\begin{array} { r } 0.0013 \\\times \quad 7.4 \\\hline\end{array}$

Solve. -Find the total monthly cost of owning and maintaining a car given the information shown. Monthly car payment: $315.58 Monthly insurance cost: $63.70 Average cost of gasoline per month: $112.50 Average maintenance cost per month: $18.50

Solve. -Find the perimeter of the figure below.

Round the numbers so that there is only one non-zero digit, and estimate the answer. Then perform the indicated operation to find the exact answer. -544.4 - 5.039

Solve. -Normal body temperature is 98.6°F. Ellen's temperature is 103.1°F. How many degrees above normal body temperature is this?

Multiply. - $\begin{array}{l}  0.189\\×   8.1\\\hline\end{array}$

Solve. -Mr. Chung grosses $500 a week. If his take-home pay is $419.52, how much money was deducted from his gross weekly pay?

Multiply. - $\begin{array} { r } 0.02\\\times \quad 0.4 \\ \hline \end{array}$

Multiply. - $\begin{array} { r } 0.0010 \\\times \quad 18.43 \\\hline\end{array}$

Solve. -Last year, Lance's average telephone bill was $83.65. Last month, his telephone bill was $113.60. How much above last year's average was last month's bill?

Solve. -Phillip bought a video for $11.62. If he paid with two $10 bills, what was his change?

Solve. -One week in May in the town of Greenleaf, it rained 1.19 inches on Tuesday, 2.89 inches on Thursday, and 1.82 inches on Saturday. It didn't rain the other four days. What was the total rainfall for the week?

Multiply. - $\begin{array} { r } 81.5 \\\times \quad 6.2 \\\hline\end{array}$

Solve. -In a practice run, a race car driver's speed is clocked at 141.456 mph at the end of his first lap, and at 165.917 mph at the end of the next lap. How much faster was he driving at the end of the second lap?

Multiply. - $\begin{array} { r } 0.409 \\\times \quad 0.2 \\\hline\end{array}$

Solve. -Juan is planning a border for his triangular-shaped garden. One side of the garden is 13.8 feet long, another side is 17.5 feet long, and the third side is 21.5 feet long. Find the amount of border material needed.

Round the numbers so that there is only one non-zero digit, and estimate the answer. Then perform the indicated operation to find the exact answer. -91.9 - 9.19

Solve. -Find the perimeter of the rectangle.

Solve. -Tameeka wanted to know the total number of hours she worked this week. Her time card indicated the following hours: Monday, 1.02 hours; Tuesday, 2.55 hours; Thursday, 1.01 hours. How many hours has Tameeka worked?