Use mathematical induction to prove the formula for every positive integer n. Show all your work. $\sum _ { i = 1 } ^ { n } i ( i + 4 ) = \frac { n ( n + 1 ) ( 2 n + 13 ) } { 6 }$

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The Answer of Use mathematical induction to prove the formula for every positive integer n. Show all your work. $\sum _ { i = 1 } ^ { n } i ( i + 4 ) = \frac { n ( n + 1 ) ( 2 n + 13 ) } { 6 }$

Use Mathematical Induction to Prove the Formula for Every Positive ∑i=1ni(i+4)=n(n+1)(2n+13)6\sum _ { i = 1 } ^ { n } i ( i + 4 ) = \frac { n ( n + 1 ) ( 2 n + 13 ) } { 6 }∑i=1n​i(i+4)=6n(n+1)(2n+13)​

Use Mathematical Induction to Prove the Formula for Every Positive $\sum _ { i = 1 } ^ { n } i ( i + 4 ) = \frac { n ( n + 1 ) ( 2 n + 13 ) } { 6 }$