Find the mean and median of $f ( x ) = \frac { 1 } { 17 } , [ 0,17 ]$ .
A) $\begin{array} { l l }
\text { mean: } & 34.00 \
\text { median: } & 34.00
\end{array}$
B) $\begin{array} { l l }
\text { mean: } & 34.00 \
\text { median: } & 0.12
\end{array}$
C) $\begin{array} { l l }
\text { mean: } & 5.67 \
\text { median: } & 0.50
\end{array}$
D) $\begin{array} { l l }
\text { mean: } & 8.50 \
\text { median: } & 8.50
\end{array}$
E) $\begin{array} { l l }
\text { mean: } & 0.50 \
\text { median: } & 0.50
\end{array}$

Question

Find the mean and median of $f ( x ) = \frac { 1 } { 17 } , [ 0,17 ]$ .
A) $\begin{array} { l l } 
\text { mean: } & 34.00 \
\text { median: } & 34.00
\end{array}$
B) $\begin{array} { l l } 
\text { mean: } & 34.00 \
\text { median: } & 0.12
\end{array}$
C) $\begin{array} { l l } 
\text { mean: } & 5.67 \
\text { median: } & 0.50
\end{array}$
D) $\begin{array} { l l } 
\text { mean: } & 8.50 \
\text { median: } & 8.50
\end{array}$
E) $\begin{array} { l l } 
\text { mean: } & 0.50 \
\text { median: } & 0.50
\end{array}$

Quizplus · Accepted Answer

The mean of a uniform distribution on the interval $[a, b]$ is $\frac{a + b}{2}$, and the median is also the midpoint of the interval. For $f(x) = \frac{1}{17}$ on the interval $[0, 17]$, both the mean and median are $\frac{0 + 17}{2} = 8.5$.

Find the Mean and Median Of f(x)=117,[0,17]f ( x ) = \frac { 1 } { 17 } , [ 0,17 ]f(x)=171​,[0,17]

Find the Mean and Median Of $f ( x ) = \frac { 1 } { 17 } , [ 0,17 ]$