Solve.
-$$9 x ^ { 2 } = - 20 x - 3$$
A) $\frac { - 10 \pm \sqrt { 73 } } { 18 }$
B) $\frac { - 10 \pm \sqrt { 127 } } { 9 }$
C) $\frac { - 20 \pm \sqrt { 73 } } { 9 }$
D) $\frac { - 10 \pm \sqrt { 73 } } { 9 }$

Question

Quizplus · Accepted Answer

Rearrange the equation to $9x^2 + 20x + 3 = 0$ and use the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ with $a = 9$, $b = 20$, and $c = 3$. This gives $x = \frac{-20 \pm \sqrt{400 - 108}}{18} = \frac{-20 \pm \sqrt{292}}{18} = \frac{-10 \pm \sqrt{73}}{9}$.

Solve - 9x2=−20x−39 x ^ { 2 } = - 20 x - 39x2=−20x−3

Solve
- $9 x ^ { 2 } = - 20 x - 3$