Solve.
-$$2 x ^ { 2 } + 6 x = - 1$$
A) $\frac { - 3 \pm \sqrt { 7 } } { 4 }$
B) $\frac { - 6 \pm \sqrt { 7 } } { 2 }$
C) $\frac { - 3 \pm \sqrt { 11 } } { 2 }$
D) $\frac { - 3 \pm \sqrt { 7 } } { 2 }$

Question

Quizplus · Accepted Answer

The equation can be rewritten as $2x^2 + 6x + 1 = 0$. Using the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = 2$, $b = 6$, and $c = 1$, we get $x = \frac{-6 \pm \sqrt{36 - 8}}{4} = \frac{-6 \pm \sqrt{28}}{4} = \frac{-6 \pm 2\sqrt{7}}{4} = \frac{-3 \pm \sqrt{7}}{2}$.

Solve - 2x2+6x=−12 x ^ { 2 } + 6 x = - 12x2+6x=−1

Solve
- $2 x ^ { 2 } + 6 x = - 1$