Find the integral using an appropriate trigonometric substitution. Select the correct answer.
$$\int \frac { x ^ { 3 } } { \sqrt { x ^ { 2 } + 1 } } d x$$
A) $\frac { 1 } { 3 } \left( x ^ { 2 } + 1 \right) ^ { 3 / 2 } \sqrt { x ^ { 2 } + 1 } + C$
B) $\frac { 1 } { 3 } \left( x ^ { 2 } - 2 \right) \sqrt { x ^ { 2 } + 1 } + C$
C) $\frac { 1 } { 3 } \left( x ^ { 2 } + 2 \right) \sqrt { x ^ { 2 } + 1 } + C$
D) $\frac { 1 } { 3 } \left( x ^ { 2 } - 1 \right) ^ { 3 / 2 } \sqrt { x ^ { 2 } + 1 } + C$

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The Answer of Find the integral using an appropriate trigonometric substitution. Select the correct answer.
$$\int \frac { x ^ { 3 } } { \sqrt { x ^ { 2 } + 1 } } d x$$
A) $\frac { 1 } { 3 } \left( x ^ { 2 } + 1 \right) ^ { 3 / 2 } \sqrt { x ^ { 2 } + 1 } + C$
B) $\frac { 1 } { 3 } \left( x ^ { 2 } - 2 \right) \sqrt { x ^ { 2 } + 1 } + C$
C) $\frac { 1 } { 3 } \left( x ^ { 2 } + 2 \right) \sqrt { x ^ { 2 } + 1 } + C$
D) $\frac { 1 } { 3 } \left( x ^ { 2 } - 1 \right) ^ { 3 / 2 } \sqrt { x ^ { 2 } + 1 } + C$

Find the Integral Using an Appropriate Trigonometric Substitution ∫x3x2+1dx\int \frac { x ^ { 3 } } { \sqrt { x ^ { 2 } + 1 } } d x∫x2+1​x3​dx

Find the Integral Using an Appropriate Trigonometric Substitution $\int \frac { x ^ { 3 } } { \sqrt { x ^ { 2 } + 1 } } d x$