Solve the exponential equation algebraically. Approximate the result to three decimal places.
$e ^ { 2 x } - 5 e ^ { x } - 6 = 0$
A)$\ln 6 \approx 3.792$
B) $\ln 6 \approx 2.792$
C) $\ln 6 \approx 0.792$
D) $\ln 6 \approx - 0.208$
E) $\ln 6 \approx 1.792$

Question

Solve the exponential equation algebraically. Approximate the result to three decimal places. 
$e ^ { 2 x } - 5 e ^ { x } - 6 = 0$ 
A)$\ln 6 \approx 3.792$
B) $\ln 6 \approx 2.792$
C) $\ln 6 \approx 0.792$
D) $\ln 6 \approx - 0.208$
E) $\ln 6 \approx 1.792$

Quizplus · Accepted Answer

The Answer is E

Solve the Exponential Equation Algebraically e2x−5ex−6=0e ^ { 2 x } - 5 e ^ { x } - 6 = 0e2x−5ex−6=0

Solve the Exponential Equation Algebraically $e ^ { 2 x } - 5 e ^ { x } - 6 = 0$