$\text { Find } ( f / g ) ( x ) \text {. What is the domain of } f / g \text { ? }$
$f ( x ) = x ^ { 2 } , \quad g ( x ) = 5 x - 7$
A) $\frac { 5 x - 7 } { x ^ { 2 } }$; all real numbers $x$ except $x = 0$
B) $- \frac { x ^ { 2 } } { 5 x - 7 }$; all real numbers $x$.
C) $\frac { 5 x + 7 } { x ^ { 2 } }$; all real numbers $x$ except $x = 0$
D)
$\frac { x ^ { 2 } } { 5 x + 7 } ;$ all real numbers $x$ except $x = \frac { 5 } { 7 }$
E)
$\frac { x ^ { 2 } } { 5 x - 7 } ;$ all real numbers $x$ except $x = \frac { 7 } { 5 }$

Question

$\text { Find } ( f / g ) ( x ) \text {. What is the domain of } f / g \text { ? }$ 
$f ( x ) = x ^ { 2 } , \quad g ( x ) = 5 x - 7$
A) $\frac { 5 x - 7 } { x ^ { 2 } }$; all real numbers $x$ except $x = 0$
B) $- \frac { x ^ { 2 } } { 5 x - 7 }$; all real numbers $x$.
C) $\frac { 5 x + 7 } { x ^ { 2 } }$; all real numbers $x$ except $x = 0$
D)
$\frac { x ^ { 2 } } { 5 x + 7 } ;$ all real numbers $x$ except $x = \frac { 5 } { 7 }$
E)
$\frac { x ^ { 2 } } { 5 x - 7 } ;$ all real numbers $x$ except $x = \frac { 7 } { 5 }$

Quizplus · Accepted Answer

The division $f/g$ of the given functions $f(x) = x^2$ and $g(x) = 5x - 7$ results in $\frac{x^2}{5x - 7}$. The domain of this function excludes values of $x$ that make the denominator zero. Solving $5x - 7 = 0$ gives $x = \frac{7}{5}$, so the domain is all real numbers except $x = \frac{7}{5}$.

Find (f/g)(x). What is the domain of f/g ? \text { Find } ( f / g ) ( x ) \text {. What is the domain of } f / g \text { ? } Find (f/g)(x). What is the domain of f/g ?

$\text { Find } ( f / g ) ( x ) \text {. What is the domain of } f / g \text { ? }$