Evaluate the function for the indicated values. $f ( x ) = 4 \llbracket x + 8 \rrbracket + 8$
(i) $f ( 5 )$
(ii) $f ( - 52.7 )$
(iii) $f \left( \frac { 2 } { 3 } \right)$
A) $\begin{array} { l l l } \text { (i) } 60 & \text { (ii) } - 168 & \text { (iii) } 44 \end{array}$
B) $\begin{array} { l l l } \text { (i) } 60 & \text { (ii) } - 168 & \text { (iii) } 40 \end{array}$
C) $\begin{array} { l l l } \text { (i) } 61 & \text { (ii) } - 172 & \text { (iii) } 44 \end{array}$
D) $\begin{array} { l l l } \text { (i) } 61 & \text { (ii) } - 172 & \text { (iii) } 40 \end{array}$
E) $\begin{array} { l l l } \text { (i) } 60 & \text { (ii) } - 172 & \text { (iii) } 40 \end{array}$

Question

Quizplus · Accepted Answer

The function uses the floor function $\llbracket x \rrbracket$, which rounds down to the nearest integer. Calculating each:  (i) $f(5) = 4 \llbracket 5 + 8 \rrbracket + 8 = 4 \times 13 + 8 = 60$  (ii) $f(-52.7) = 4 \llbracket -52.7 + 8 \rrbracket + 8 = 4 \times -45 + 8 = -172$  (iii) $f\left(\frac{2}{3}\right) = 4 \llbracket \frac{2}{3} + 8 \rrbracket + 8 = 4 \times 8 + 8 = 40$

Evaluate the Function for the Indicated Values f(x)=4⟦x+8⟧+8f ( x ) = 4 \llbracket x + 8 \rrbracket + 8f(x)=4[[x+8]]+8

Evaluate the Function for the Indicated Values $f ( x ) = 4 \llbracket x + 8 \rrbracket + 8$