Use the intercept form to find the equation of the line with the given intercepts. The intercept form of the equation of a line with intercepts $( a , 0 ) \text { and } ( 0 , b ) \text { is }$ $\frac { x } { a } + \frac { y } { b } = 1 , a \neq 0 , b \neq 0$
Point on line: $( - 8,3 )$
$x$-intercept: $( c , 0 )$
$y$-intercept: $( 0 , c ) , \quad c \neq 0$
A) $- x - y - 5 = 0$
B) $- x + y - 5 = 0$
C) $x + y - 3 = 0$
D) $x + y - 5 = 0$
E) $x - y - 5 = 0$

Question

Quizplus · Accepted Answer

Given the point $(-8, 3)$ lies on the line, and both intercepts are $(c, 0)$ and $(0, c)$, substituting these into the intercept form $\frac{x}{c} + \frac{y}{c} = 1$ and simplifying gives $x + y = c$. Substituting the point $(-8, 3)$ into this equation gives $-8 + 3 = -5$, so $c = -5$, leading to the equation $x + y - 5 = 0$.

Use the Intercept Form to Find the Equation of the Line