Show that the points form the vertices of the indicated polygon. Right triangle: $( 5,5 ) , ( 6,4 ) , ( - 2 , - 4 )$
A) $( \sqrt { 2 } ) ^ { 2 } + ( \sqrt { 128 } ) ^ { 2 } = ( \sqrt { 130 } ) ^ { 2 }$
B) $( \sqrt { 52 } ) ^ { 2 } + ( \sqrt { 128 } ) ^ { 2 } = ( \sqrt { 130 } ) ^ { 2 }$
C) $( \sqrt { 11 } ) ^ { 2 } + ( \sqrt { 128 } ) ^ { 2 } = ( \sqrt { 130 } ) ^ { 2 }$
D) $( \sqrt { 50 } ) ^ { 2 } + ( \sqrt { 128 } ) ^ { 2 } = ( \sqrt { 130 } ) ^ { 2 }$
E) $( \sqrt { 7 } ) ^ { 2 } + ( \sqrt { 128 } ) ^ { 2 } = ( \sqrt { 130 } ) ^ { 2 }$

Question

Quizplus · Accepted Answer

The distance between (5,5) and (6,4) is $\sqrt{(6-5)^2+(4-5)^2}=\sqrt{1+1}=\sqrt{2}$.The distance between (6,4) and (-2,-4) is $\sqrt{(-2-6)^2+(-4-4)^2}=\sqrt{64+64}=\sqrt{128}$.The distance between (-2,-4) and (5,5) is $\sqrt{(5+2)^2+(5+4)^2}=\sqrt{49+81}=\sqrt{130}$.So, the points form the vertices of a right triangle.

Show That the Points Form the Vertices of the Indicated (5,5),(6,4),(−2,−4)( 5,5 ) , ( 6,4 ) , ( - 2 , - 4 )(5,5),(6,4),(−2,−4)

Show That the Points Form the Vertices of the Indicated $( 5,5 ) , ( 6,4 ) , ( - 2 , - 4 )$