The position of a car is given by the values in the following table. $\begin{array}{|c|c|c|c|c|c|}
\hline t \text { (seconds) } & 0 & 1 & 2 & 3 & 4 \
\hline s \text { (meters) } & 0 & 21.9 & 25.8 & 69.2 & 92.2 \
\hline
\end{array}$

Find the average velocity for the time period beginning when $t = 2$ and lasting 2 seconds.
A) $46.1 \mathrm { ft } / \mathrm { s }$
B) $31.9 \mathrm { ft } / \mathrm { s }$
C) $33.5 \mathrm { ft } / \mathrm { s }$
D) $33.8 \mathrm { ft } / \mathrm { s }$
E) $33.2 \mathrm { ft } / \mathrm { s }$

Question

The position of a car is given by the values in the following table. $\begin{array}{|c|c|c|c|c|c|}
\hline t \text { (seconds) } & 0 & 1 & 2 & 3 & 4 \
\hline s \text { (meters) } & 0 & 21.9 & 25.8 & 69.2 & 92.2 \
\hline
\end{array}$

Find the average velocity for the time period beginning when $t = 2$ and lasting 2 seconds.
A) $46.1 \mathrm { ft } / \mathrm { s }$
B) $31.9 \mathrm { ft } / \mathrm { s }$
C) $33.5 \mathrm { ft } / \mathrm { s }$
D) $33.8 \mathrm { ft } / \mathrm { s }$
E) $33.2 \mathrm { ft } / \mathrm { s }$

Quizplus · Accepted Answer

The average velocity is calculated as the change in position divided by the change in time. For the time period from $t = 2$ to $t = 4$ seconds, the change in position is $92.2 - 25.8 = 66.4$ meters, and the change in time is $4 - 2 = 2$ seconds. Thus, the average velocity is $66.4 \, \text{meters} / 2 \, \text{seconds} = 33.2 \, \text{meters/second}$.

The Position of a Car Is Given by the Values