If a rock is thrown upward on the planet Mars with a velocity of $12 \mathrm {~m} / \mathrm { s }$, its height in meters $t$ seconds later is given by $y = 12 t - 1.92 t ^ { 2 }$
Find the average velocity over the time interval $[ 2,3 ]$.
A) $-0.6 \mathrm {~m} / \mathrm { s }$
B) $4.4 \mathrm {~m} / \mathrm { s }$
C) $2.4 \mathrm {~m} / \mathrm { s }$
D) $3.4 \mathrm {~m} / \mathrm { s }$
E) $1.4 \mathrm {~m} / \mathrm { s }$

Question

Quizplus · Accepted Answer

The average velocity is calculated as the change in height divided by the change in time: $(y(3) - y(2)) / (3 - 2)$. Substituting the values, $y(3) = 12(3) - 1.92(3)^2 = 36 - 17.28 = 18.72$ and $y(2) = 12(2) - 1.92(2)^2 = 24 - 7.68 = 16.32$. Thus, the average velocity is $(18.72 - 16.32) / 1 = 2.4 \mathrm {~m} / \mathrm { s }$.

If a Rock Is Thrown Upward on the Planet Mars 12 m/s12 \mathrm {~m} / \mathrm { s }12 m/s

If a Rock Is Thrown Upward on the Planet Mars $12 \mathrm {~m} / \mathrm { s }$