Find the derivative of the function. $$y = 3 \cos ^ { - 1 } \left( \sin ^ { - 1 } t \right)$$
A)
$$y ^ { t } = - \frac { 3 } { \sqrt { \left( 1 - t ^ { 2 } \right) \left( 1 - \left( \sin ^ { - 1 } ( t ) \right) ^ { 2 } \right) } }$$
B)
$$y ^ { t } = - \frac { 3 } { \sqrt { \left( 1 - t ^ { 2 } \right) \left( 1 - \sin ^ { - 1 } ( t ) \right) } }$$
C)
$$y ^ { \prime } = - \frac { 3 } { \sqrt { \left( 1 - t ^ { 2 } \right) } }$$
D)
$$y ^ { t } = - \frac { 3 } { \sqrt { 1 - \left( \sin ^ { - 1 } ( t ) \right) ^ { 2 } } }$$
E)
$$y ^ { t } = - \frac { 3 } { \sqrt { \left( 1 + t ^ { 2 } \right) \left( 1 + \left( \sin ^ { - 1 } ( t ) \right) ^ { 2 } \right) } }$$

Question

Quizplus · Accepted Answer

The correct answer is A because the derivative of the function is:$$y ^ { t } = - \frac { 3 } { \sqrt { \left( 1 - t ^ { 2 } \right) \left( 1 - \left( \sin ^ { - 1 } ( t ) \right) ^ { 2 } \right) } }$$

Find the Derivative of the Function y=3cos⁡−1(sin⁡−1t)y = 3 \cos ^ { - 1 } \left( \sin ^ { - 1 } t \right)y=3cos−1(sin−1t)

Find the Derivative of the Function $y = 3 \cos ^ { - 1 } \left( \sin ^ { - 1 } t \right)$