Solve system of equations by the method of substitution. $$\left\{ \begin{array} { r }
15 x ^ { 3 } - 25 y = 0 \
15 x - y = 0
\end{array} \right.$$
A) (0,0) , (-5, -75) , (5,75)
B) (0,0) , (-5,75) , (5,75)
C) (0,0) , (5, -75) , (5,75)
D) (0,0) , (-5,76) , (5,76)
E) (0,0) , (-5, -74) , (5,74)

Question

Solve system of equations by the method of substitution. $$\left\{ \begin{array} { r } 
15 x ^ { 3 } - 25 y = 0 \
15 x - y = 0
\end{array} \right.$$
A) (0,0) , (-5, -75) , (5,75)
B) (0,0) , (-5,75) , (5,75)
C) (0,0) , (5, -75) , (5,75)
D) (0,0) , (-5,76) , (5,76)
E) (0,0) , (-5, -74) , (5,74)

Quizplus · Accepted Answer

The Answer is A

Solve System of Equations by the Method of Substitution {15x3−25y=015x−y=0\left\{ \begin{array} { r } 15 x ^ { 3 } - 25 y = 0 \\15 x - y = 0\end{array} \right.{15x3−25y=015x−y=0​

Solve System of Equations by the Method of Substitution $\left\{ \begin{array} { r } 15 x ^ { 3 } - 25 y = 0 \\15 x - y = 0\end{array} \right.$