Perform the operations and simplify. $$\frac { 1 } { x - 4 } + \frac { 3 } { x + 4 } - \frac { 3 x - 4 } { x ^ { 2 } - 16 }$$
Assume that no denominators are 0 .
A) $\frac { 4 } { x + 4 }$
B) $\frac { 1 } { x + 16 }$
C) $\frac { 1 } { x + 4 }$
D) $\frac { 1 } { x - 4 }$

Question

Quizplus · Accepted Answer

The expression can be simplified by finding a common denominator, which is $x^2 - 16 = (x-4)(x+4)$. After combining the fractions and simplifying, the result is $\frac{1}{x+4}$.

Perform the Operations and Simplify 1x−4+3x+4−3x−4x2−16\frac { 1 } { x - 4 } + \frac { 3 } { x + 4 } - \frac { 3 x - 4 } { x ^ { 2 } - 16 }x−41​+x+43​−x2−163x−4​

Perform the Operations and Simplify $\frac { 1 } { x - 4 } + \frac { 3 } { x + 4 } - \frac { 3 x - 4 } { x ^ { 2 } - 16 }$